4y^2-8y+5=0

Solution for 4y^2-8y+5=0 equation:

Simplifying
4y2 + -8y + 5 = 0

Reorder the terms:
5 + -8y + 4y2 = 0

Solving
5 + -8y + 4y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
1.25 + -2y + y2 = 0

Move the constant term to the right:

Add '-1.25' to each side of the equation.
1.25 + -2y + -1.25 + y2 = 0 + -1.25

Reorder the terms:
1.25 + -1.25 + -2y + y2 = 0 + -1.25

Combine like terms: 1.25 + -1.25 = 0.00
0.00 + -2y + y2 = 0 + -1.25
-2y + y2 = 0 + -1.25

Combine like terms: 0 + -1.25 = -1.25
-2y + y2 = -1.25

The y term is -2y.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2y + 1 + y2 = -1.25 + 1

Reorder the terms:
1 + -2y + y2 = -1.25 + 1

Combine like terms: -1.25 + 1 = -0.25
1 + -2y + y2 = -0.25

Factor a perfect square on the left side:
(y + -1)(y + -1) = -0.25

Can't calculate square root of the right side.

The solution to this equation could not be determined.